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14=7x+5x^2
We move all terms to the left:
14-(7x+5x^2)=0
We get rid of parentheses
-5x^2-7x+14=0
a = -5; b = -7; c = +14;
Δ = b2-4ac
Δ = -72-4·(-5)·14
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{329}}{2*-5}=\frac{7-\sqrt{329}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{329}}{2*-5}=\frac{7+\sqrt{329}}{-10} $
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